WP Debug show only via a URL get parameter - Paste

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PHP 117

WP Debug show only via a URL get parameter By micha on 7th November 2018 02:01:37 PM

if (isset($_GET['debug']) && $_GET['debug'] == 'display') {
define('WP_DEBUG', true);
define('WP_DEBUG_DISPLAY', true);
} else if (isset($_GET['debug']) && $_GET['debug'] == 'log') {
define('WP_DEBUG', true);
define('WP_DEBUG_LOG', true);
} else {
define('WP_DEBUG', true);
define('WP_DEBUG_LOG', false);
define('WP_DEBUG_DISPLAY', false);
}

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